A5. Find the number of tiles of dimensions 1 m x 0.8 m
required to cover a floor of dimensions 80 m x 120 m.
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Answer:
12000 tiles required to cover a floor
Step-by-step explanation:
area of floor = 80 × 120
=9600 sq m
area of the tile= 0.8 sq m
let n be the number of tiles required
n×(0.8) = 9600
n=12000
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