Question

(a⁶ -1) ÷ (a² -1)

options
a² + a - 1
a³ - a² + 1
a⁴ + a² + 1
a⁴ - a² - 1

Answer 1

Answer:

The right answer is option 3-a^4+a^2+1

Step-by-step explanation:

we know the formula (a^3-b^3)=(a-b)(a^2+ab+b^2)

let (a^6-2) can be written as (a^2)^3-(1^2)^3

so (a^2)^3-(1^2)^3=(a^2)-(1^2)[(a^2)^2+(a^2*1)+1^2]/(a^2)-1

(a^2)^3-(1^2)^3= a^4+a^2+1