Math, asked by jaimilkothari2003, 6 months ago

(a⁶)³*(2)⁸*(a^-3)⁴ / (a²)⁵*(a⁵)²
simplify​

Answers

Answered by Anonymous
2

\pink\starTo simplify :-

(a⁶)³*(2)⁸*(a^-3)⁴ / (a²)⁵*(a⁵)²

\blue\starSolution :-

 =  >  \frac{ ({ {a}^{2} )}^{2}  \times  {2}^{8}  \times  ({ {a}^{ - 3}) }^{4} }{ ({ {a}^{2}) }^{5}  \times  ({ {a}^{5} )}^{2} }

 =  >  \frac{ {a}^{4} \times  {2}^{8}   \times  {a}^{( - 12)} }{ {a}^{10} \times  { {a}^{} }^{10}  }

 =  >   \frac{{a}^{8}  \times  {2}^{8} }{ {a}^{20} }

 =  >  {a}^{12}  \times  {2}^{8}

Answered by voraprachi8a56
0

Answer:

⋆ To simplify :-

(a⁶)³*(2)⁸*(a^-3)⁴ / (a²)⁵*(a⁵)²

\blue\star⋆ Solution :-

= > \frac{ ({ {a}^{2} )}^{2} \times {2}^{8} \times ({ {a}^{ - 3}) }^{4} }{ ({ {a}^{2}) }^{5} \times ({ {a}^{5} )}^{2} }=>

(a

2

)

5

×(a

5

)

2

(a

2

)

2

×2

8

×(a

−3

)

4

= > \frac{ {a}^{4} \times {2}^{8} \times {a}^{( - 12)} }{ {a}^{10} \times { {a}^{} }^{10} }=>

a

10

×a

10

a

4

×2

8

×a

(−12)

= > \frac{{a}^{8} \times {2}^{8} }{ {a}^{20} }=>

a

20

a

8

×2

8

= > {a}^{12} \times {2}^{8}=>a

12

×2

8

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