a⁶ –(b+1)³ when a =1/2,b=–3/4
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Formula of (a + b)³
(a + b)³
[(a + b)(a + b)](a + b)
[a(a + b) + b(a + b)](a + b)
(a² + ab + ab + b²) (a + b)
a ( a² + 2ab + b²) + b(a² + 2ab + b²)
a³ + 2a²b + ab² + a²b + 2ab² + b³
a³ + 3a²b + 3ab² + b³
a³ + b³ + 3a²b + 3ab²
a³ + b³ + 3ab( a + b)
Therefore ......
(a + b)³ = a³ + b³ + 3ab(a + b)
Hope it help you…
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Step-by-step explanation:
1/2³²
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