Math, asked by nadaganaprameela, 1 day ago

A6 (B4 The ratio of two numbers is 3:4 and their H.C.F is 4. What is their L.C.M.? (A) 12 (B) 16 (C) 24 (D) 48 ​

Answers

Answered by dayanidhisharma19
0

Answer:

48 (Option D)

Step-by-step explanation:

Let the numbers be 3x and 4x.

Then, their HCF =x

Given that their H.C.F is 4

So, x=4  

So, the numbers are 3x=12 and 4x=16.

LCM of 12 and 16 is 48.

Answered by junaida8080
0

Given data,

The ratio of two numbers is 3:4

Let the two numbers be 3x,4x

HCF of the given numbers is 4

As we know that the HCF is the multiple of given numbers,

Then we can take x=4

Substitute the value of x in 3x,4x

We get,

3x=3(4)=12

4x=4(4)=16

The two numbers are 12,16

As we know that the formula related to both LCM and HCF is,

Product of two numbers = LCM \times HCF

12\times16=LCM \times 4

LCM=\frac{12\times16}{4}

LCM=12\times4

LCM=48

Therefore, LCM of  12,16 is 48

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