a⁷ - 64a factorise
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3
Step-by-step explanation:
a(a^6-64)
=a(a^3-8)(a^3+8)
Answered by
11
a^7 - 64a
= a(a^6 - 64)
= a[(a³)² - (8)²]
= a(a³ - 8)(a³ + 8)
= a[(a)³ - (2)³][(a)³ - (2)³]
= a(a - b)(a² + 2a + 4)(a + b)(a² - 2a + 4).
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