Chemistry, asked by duraimahalakahmi, 1 month ago

a7|when an electron of charge e is accelerated through a potential of V volts, the associated waveleng electron will be:- h -] (2meV) Alt1 h Alt2 (meV) 2met Alt3 7. = (2meV) 2. = h​

Answers

Answered by gfastest826
1

Answer:

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Answered by soulsisters263
1

de-Broglie wavelength is given by  λ=ph

where, momentum of the particle  p=2mK

Kinetic energy of the particle  K=eV

⟹ λ=2meVh

We get   λ∝V1

Thus de-Broglie wavelength of the electron will become half if the accelerating potential is increased by a factor of 4.

I hope my answere is right, I'm not that sure tho

it's been a while since I read the chapter

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