Question

A9cm long object is placed at 90cm from a spherical mirror perpendicular to its principal axis. A real image
is formed at 30cm from the mirror. What is the radius of curvature of the mirror? {Ans: - 45 cm}​

Answer 1

Answer:

Height of object ho = 9 cm  

Focal lenght of convex lens = ? cm  

Object distance u = -90 cm  

Image distance v = 30 cm  

Image height hi = ?  

Lens formula: 1/v  -  1/u  =  1/f  

                        1/f  = 1/v -  1/u  

                               =  1/30  +  1/(-90)  

                               = -1/45

⇒  v = - 45 cm

The image distance is 45 cm on the same side of the lens as the object.

Magnification m = v/u = (-45)/(-90) = 1/2 = hi/ho = hi/9

⇒   hi = 9/2 cm

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Answer 2

Answer:

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