Physics, asked by thippareddy123456, 11 months ago

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19. A concave mirror is used to focus the image
of a flower on a nearby well 120 cm from the
flower. If a lateral magnification of 16 IS
desired, the distance of the flower from the
mirror should be
[MP PET 1986]
(a) 8cm
(b) 12cm
(C) 80cm
(d) 120 cm​

Answers

Answered by AneesKakar
11

Answer:

8cm.

Explanation:

Since, the magnification of the concave mirror is given as 16. So, if we take the image distance as v and the object distance as u. So, we get that the v/u will be 16. Again, from the question we get that the v=u+120. The concave mirror is placed at a distance of 120cm.

So, on substituting the value of the v in the magnification equation we will get that (120+u)/u=16. Hence, we will get that 120+u=16u or 15u=120. So, on solving we will get the u as 8cm.

Answered by nidaeamann
10

Answer:

Hence option A is correct

Explanation:

The simple formula for magnification is as;

M = I / O;

 = - v/ u

Where v is the distance from image, u is the distance from the object.

Distance between flower and image is 120cm

Appying the formula;

16 = - (120-u)/u ;

16u = -120 + u

15u = -120

U = - 8 cm

Hence option A is correct

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