AA+BB+CC=BAC Find the value of A, B, C
Answers
Step-by-step explanation:
A= AA+BB+CC/BC=AA/BC+B/C+C/B
B=AA+BB+CC/AC=A/C+BB/AC+C/A
C=AA+BB+CC/AB=A/B+B/A+CC/AB
HENCE VALUES OF A,B&C ARE AS GIVEN ABOVE
Answer:
99+11+88=198
Step-by-step explanation:
AA+BB+CC=BAC
Substitute Maximum Posssible Values:
99+88+77=264
So,B is less than 300
(i.e.,) B is 1 or 2 (0 is not Possible because A,B,C are +ve numbers)
=====>Lets take Units digit:
A+B+C=C
A+B=0 (0 is a units digit)
Substitute A values:
A+1=0 or A+2=0
9+1=0(10) or 8+2=0(10)
Above solution we get sum as 10 where 1 is a tens digit
and 0 is a units digit.
We get,
A=9 and B=1
(or)
A=8 and B=82
Substitute in AA+BB+CC=BAC
99+11+CC=19C (or) 88+22+CC=28C
110+CC=19C (or) 110+CC=28C 28C>264 (Maximum Possible
sum 99+88+77=264)
So,it is not Possible.
=======>Lets take Tens digit from 110+CC=19C:
1+C=9
C=8
Finally we get A=9 B=1 C=8
99+11+88=198
Easy Explanation In Puzzle Pedia:
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