Question

aa block of mass 10 kg is moving on a rough surface the frictional force acting on block is v =4m/s F=20N MEU=0.6

Answer 1

Hello dear,

● Answer-

F = 60 N

● Explanation-

# Given-

m = 10 kg

μ = 0.6

# Solution-

Frictional force acting on the block is given by-

F = μN

Where, N = normal reaction

Here, weight of the block acts as normal reaction.

F = μmg

F = 0.6 × 10 × 10

F = 60 N

Therefore, frictional force acting on the block is 60 N.

Hope it helps...