Question

aa boy throws a ball upward with velocity of 72 km/h. find the height and final velocity?​

Answer 1

Answer:

Initial velocity , u = 72km/hr

= 20m/s

Final velocity = v

Height = h

At maximum height (h) , v=0

Using 1st equation of motion ,

v = u+at

0 = 20 + (-10)t

t = 20/10 = 2 sec

Now, using 2nd equation of motion;

s = ut + 1/2 at^2

h = 20(2) + 1/2(-10)(2)^2

= 40 - 5×4

= 40 - 20

= 20m

Hope it helps!