Physics, asked by karruu3236, 10 months ago

Aa force 98n is required to pull a body of mass 100kg over the surface of ice calculate the coefficient of friction between body and the surface of the ice

Answers

Answered by mdanish167

Answer: 0.1

Explanation:

F= 98 N

force of friction (f) = $\mu \times Normal Reaction$

and Normal reaction = Mg

limiting friction required to pull the body the ice = $\mu \times Mg$

at limiting case when the block is about to move

F = f

98 = $\mu \times 100 \times 9.8$

$\mu=0.1$

Answered by Anonymous

Answer:

Explanation:

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21.09.2020

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