Question

aA man has to go 50m due north,40m due east nad 20m due south to reach a field.(a)what is distance he has to walk to reach the field?.b what is his displacement from his house to the field

Answer 1

$\Large{\underline{\underline{\bf{Solution :}}}}$

We know that,

Distance = Total Path covered.

So,

Distance = 50 + 20 + 40

→Distance = 110 m

$\rule{200}{2}$

Now,

Fir, Displacement we will find the side of the triangle.

So,

50 m - 20 m

→30 m

_________________________

$\sf{→Displacement = \sqrt{(30)^2 + (40)^2}} \\ \\ \sf{→Displacement = \sqrt{1600 + 900}} \\ \\ \sf{→Displacement = \sqrt{2500}} \\ \\ \sf{→Displacement = \pm 50 \: m}$

As, Displacement can't be negative.

So, Displacement = 50 m