Math, asked by Anonymous, 7 months ago

आंसर देदो..... वन्देमातरम्​

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Answered by Anonymous
11

Answer:

1:- two digits no- 80

Probability = 80/90 = 8/9 ans.

2:- no- 4,9,16,25,36,49,64,81

Probability = 8/90 = 4/45 ans.

3:- no- 5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90

Probability = 18/90 = 1/5 ans.

Step-by-step explanation:

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Answered by pulakmath007
13

\displaystyle\huge\red{\underline{\underline{Solution}}}

The box contains 90 discs which are numbered from 1 to 90

So the total number of discs = 90

So the total number of possible outcomes = 90

1.

Let A be the event that the resulting disc is numbered a TWO DIGIT NUMBER

Since the number of two digit number from 1 to 90 is = 90 - 10 + 1 = 81

So The the total number of possible outcomes for the event A is = 81

So the required probability = P(A) =   \displaystyle \: \frac{81}{90}  =  \frac{9}{10}

2.

Let B be the event that the resulting disc is numbered a PERFECT SQUARE NUMBER

Since the PERFECT SQUARE NUMBER from 1 to 90 is = 4, 9, 16, 25, 36, 49, 64, 81

So The the total number of possible outcomes for the event B is = 8

So the required probability = P(B) = \displaystyle \:  \frac{8}{90}

3.

Let D be the event that the resulting disc is numbered DIVISIBLE BY 5

Since the numbers DIVISIBLE BY 5 from 1 to 90 are =

5, 10, 15 20, 25, 30,35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90

So The the total number of possible outcomes for the event D is = 18

So the required probability = P(D) =  \displaystyle \:  \frac{18}{90}  =  \frac{1}{5}

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