Question

aA train starting from a railway station and moving with uniform acceleration attains a speed 40 km h-¹ in 10 minutes. Find its acceleration​

Answer 1

As the train started from a railway station, so initial velocity of train, u = 0

Final velocity of train, v = 40 kmph

Final velocity, v = 40 × 5/18 = 11.11 m/s

Assuming uniform acceleration of ‘a’ m/second square

Time taken by train to get it's final velocity, t = 10 minutes = 600 seconds

Using first equation of motion,

V = u + at

11.11 = 0 + a×600

a = 11.11/600 = 0.0185 m/second square.

So, required acceleration , a = 0.0185 m/second square.

Hope you like it

Answer 2

Given:

• Final Velocity of train, v = 40 km/h = 11.11 m/s
• Time taken by train, t = 10 min = 10 × 60 = 600 s

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To find:

• Acceleration?

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Solution:

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We know that,

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Acceleration:

• Acceleration is the rate of change of velocity with time.
• It is a vector quantity.

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$\star\;{\boxed{\sf{\purple{Acceleration,\:a = \dfrac{Final\: Velocity - Initial\: Velocity}{Time}}}}}$

Here,

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• Initial Velocity, u = 0 m/s ⠀⠀⠀⠀[ Train starts from the rest ]
• Final Velocity, v = 11.11 m/s
• Time taken, t = 600 s

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★ Now, Putting values in formula,

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$:\implies\sf a = \dfrac{11.11 - 0}{600}$

$:\implies\sf a = \dfrac{11.11}{600}$

$:\implies{\boxed{\sf{\pink{a = 0.0185\;m/s^2}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Hence,\; Acceleration\;of\;train\; is\; \bf{0.0185\;m/s^2}.}}}$