Question

AA wall is of the form of a trapezium with height 4m and parallel sides being 3m and 5m then the cost of painting the wall if it the rate of pain is Rs 25 per.sq.m

please answer step by step
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Answer 1

Given, height of trapezium =3 m, two sides length =3 m and =5 m.

Area of trapezium =

2

side

1

+side

2

×height

Area of wall =

2

1

(5+3)×4

=

2

1

×8×4=16 sq. m

The rate of painting is Rs. 25 per square metre.

Thus cost of painting for 16 sq. m is =16×25= Rs. 400.

Step-by-step explanation:

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Answer 2

Answer:

400 ₹

Step-by-step explanation:

area of trapezoid = 1/2 (3+5) × 4

= 1/2 × 8 × 4

= 1/2 × 32

= 16 m²

25 × 16

= 400 ₹ m