AAA+BBB+CCC=BAAC find A
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aaa+bbb+ccc=baac
Understanding that the question is using variables to represent single digits, rewrite the question as
100a+10a+a+100b+10b+b+100c+10c+c=1000b+100a+10a+c
subtract 100a+10a+c from both sides
a+100b+10b+b+100c+10c=1000b
Then subtract 100b+10b+b from both sides
a+100c+10c=889b
a+110c=889b
a=889b-110c
Recall that a is a single digit number between 1 and 9, as are b and c
So 110c is 110, 220, 330, 440, 550, 660, 770, 880, or 990
And 889 b is similarly 889, 1778, 2667, 3556,4445,5335, 6223, 7112, or 8001
But the only combination there with a single digit difference is
9=889-880
So a=9, b=1, and c=8
999+111+888=1998 which is baac
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