Math, asked by Sasmithkodiganti, 6 months ago

AAA+BBB+CCC=BAAC find A

Answers

Answered by Anonymous
2

Answer:

aaa+bbb+ccc=baac

Understanding that the question is using variables to represent single digits, rewrite the question as

100a+10a+a+100b+10b+b+100c+10c+c=1000b+100a+10a+c

subtract 100a+10a+c from both sides

a+100b+10b+b+100c+10c=1000b

Then subtract 100b+10b+b from both sides

a+100c+10c=889b

a+110c=889b

a=889b-110c

Recall that a is a single digit number between 1 and 9, as are b and c

So 110c is 110, 220, 330, 440, 550, 660, 770, 880, or 990

And 889 b is similarly 889, 1778, 2667, 3556,4445,5335, 6223, 7112, or 8001

But the only combination there with a single digit difference is

9=889-880

So a=9, b=1, and c=8

999+111+888=1998 which is baac

Step-by-step explanation:

Answered by hoori622010
0

Answer:

hope it helps

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