Question

Aabb is a 4 digit perfect square number. find a+b

Answer 1

Answer:

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Step-by-step explanation:

The number aabb is

1000a+100a+10b+b=

1100a+11b=

11(100a+b)

To be a perfect square, each factor must appear an even number of times. Then (100a+b) must be a multiple of 11, which in this case is achieved by making that a+b=11.

So, the possibles a and b are 9 and 2, 8 and 3, 7 and 4, 6 and 5, or the opposite order.