Question

AABC and ABDE are two equilateral triangles such that D is the mid-point of BC,
Find the ratio of the areas of AABC and ABDE,
explain it properly​

Answer 1

Answer:

4:1

Step-by-step explanation:

area of abc=√3/4 (side)^2 = √3/4 x^2

area of bde=√3/4 (side)^2 = √3/4 (x/2)^2

ratio of area of abc to area of bde

= (√3/4 x^2)/(√3/4 (x/2)^2)

=x^2/x^2/4

=1/1/4

=4/1

hence the ratio will be 4:1.