Question

AABC is a right-angled triangle with angle B = 90°. A circle is drawn circumscribing the ∆ABC. State with reason, what will be the position of the centre of this circle.​

Answer 1

Answer:

Given ∠B=90∘,AB=28cm,BC=21cm

Area of shaded region=ar△ABC+area of semicircle AC-ar quarter circle BC

=21×BC×AB+21×π(2AC)2−41×π(BC)2

=[21×21×28]+[21×722×41(282+212)2]−41×722×21×21

=294+[2811×1225]−346.5

=294+481.25−346.5=428.75㎠

Answer 2

Answer:

Answer:Given ∠B=90

Answer:Given ∠B=90 ∘

Answer:Given ∠B=90 ∘ ,AB=28cm,BC=21cm

Answer:Given ∠B=90 ∘ ,AB=28cm,BC=21cmArea of shaded region=ar△ABC+area of semicircle AC-ar quarter circle BC

(answer on top )

=294+481.25−346.5=428.75㎠

_hope it helps you_