Question

AABC is a right angled triangle with ZB = 90°. PAB, QAC and RBC are
the equilateral triangles constructed on sides AB, AC and BC respectively.
Prove : A(APAB) + A(ARBC) = A(AQAC).​

Answer 1

Step-by-step explanation:

hey mate here is Ur answer-

here in the diagram, triangle QAC lies on the hypotenuse

by Pythagoras theorem,

AC^2 =AB^2 + BC^2

.

as the one side the triangle lie on the side, and they all three are equilateral triangle all sides are equal

therefore, triangle PAB + triangle RBC = triangle QBC

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