Question

AABC is a triangle with AB =AC and BC = 9 cm. If the height from A to BC is 6 cm then the integral
part of the height from C to AB in cm, is​

Answer 1

Answer:

Area of \Delta ABC=\frac{1}{2}\times base\times height\

=\frac{1}{2}\times9cm\times6cm=27cm^2

Area of \Delta ABC=\frac{1}{2}\times AB\times CE

27cm^2=\frac{1}{2}\times7.5cm\times CE

CE=\frac{27\times2}{7.5}CM=\frac{36}{5}cm=7.2cm