Question

AABC is right-angled at A. AD is perpendicular to BC, AB=5 cm, BC = 13 cm and
AC-12 em. Find the area of AABC. Also, find the length of AD.
12 cm
13 cm​

Answer 1

Answer:In right angles triangle BAC, AB=5cm and AC=12cm

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle=

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height=

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC=

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC=

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30=

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD=

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD= 13

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD= 1330×2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD= 1330×2

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD= 1330×2 =

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD= 1330×2 = 13

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD= 1330×2 = 1360

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD= 1330×2 = 1360

In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 21 ×base×height= 21 ×AB×AC= 21 ×5×12=30cm 2 Now, in ΔABC,Area of triangle ABC= 21 ×BC×AD⇒30= 21 ×13×AD⇒ AD= 1330×2 = 1360 cm.

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Explanation:

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