Question

AABC is right angled at A (Fig 11.25). AD is perpendicular to BC. If AB = 5 cm. BC 13 cm and AC =12 cm, Find the area of AABC. Also find the length of AD.
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Answer 1

Answer:

area of AABC is 30 and length of AD is -3.35

Step-by-step explanation:

(I) Area of AABC

AABC is a right angled triangle

formula of area of AABC =1/2*base*hieght

=1/2*12*5

=6*5=30

(ii) Length of AD

ABAD is right angled because ADis perpendicular on BC.

By Pythagoras theorem

${ab}^{2} = {bd}^{2} + {ad}^{2}$

${5}^{2} = {6.5}^{2} + {ad}^{2}$

$25 = 36.25 + {ad}^{2}$

$25 - 36.25 = {ad}^{2}$

$- 11.25 = {ad}^{2}$

$\sqrt{ - 11.25} = ad$

ad=-3.35

I am sure that area of AABC is right but length of AD may be wrong