Question

आकृतीमध्ये ABC = 90° , AB = 3x , BC = 4x आणि AC = 30 तर
3x
30
(a) पायथागोरसच्या प्रमेयाचा वापर करून x ची किंमत काढा.
(b) रेख AB व रेख BC ची लांबी काढा.
B
4x
(c)A (ΔABC ) काढा .​

Answer 1

Step-by-step explanation:

a}angle abc =90° angle B=90°

by using pgt

ac^2=ab^2+bc^2

30^2=3x^2+4x^2

900=9x^2+16x^2

900=25x^2

squaring on both the sides

30=5x

x=30/5

x=6

B}AB=3x

3×6

AB= 18

BC=4x

4×6

BC=24

3}area of triangle ABC =1/2*×base×height

1/2×24×18

=216

hope this ans are useful for you

Answer 2

(a)

By using pythagoras theorem,

(AC)²=(AB)²+(BC)²

(30)²=(3)²+(4)²

900=9+16

900=25

X²=900/25

X²=√6

X=6cm

(b)

AB=3x

AB=3×6

AB=18cm

Now,

BC=4x

BC=4×6

BC=24cm.

(c)

A(∆ABC)=½×Base×Height

A(∆ABC)=½×24×18

A(∆ABC)=216