Math, asked by pkmahto1099, 8 months ago

aamount if 65000 is invested in three investment at the rate of 6%,8%and 9% per annum respectively.the total income is 4800 the income frim third investment is rs.600 more than incom efrom second investment.using matrix algerba, determine the amount of each investments

Answers

Answered by ItsUnicorn
0

Answer:

hope it helps u............

Attachments:
Answered by manojkumarj
0

Answer:

Step-by-step explanation:

an amount of 65,000 is invested in three bonds at the rates of 6 % , 8 %, and 10% per annum   respectively

amount invested = rs 65000

bond 1   = rs   1000 a

bond 2 = rs   1000 b

bond 3 = 65000 - 1000a - 1000b =   1000(65 - a -b) rs

income from bond 1 = (6/100)* 1000a = 60a rs

income from bond 2 = (8/100) * 1000b = 80b   rs

income from bond 3 = (10/100) * 1000(65-a-b) = 100(65 - a - b)   rs

60a + 80b + 100(65 - a - b) = 4800

=> 40a + 20b = 1700

=> 2a + b = 85   - eq 1

100(65-a-b) = 600 + 80b

=> 100a + 180b = 5900

=> 5a + 9b = 295   - eq 2

9 * eq1 - eq2

13a = 470

=> a = 470/13

2(470/13) + b = 85

=> b = 165/13

first bond = 1000a =   47/13   =   rs 36153.85

second bond = 1000b = 165000/13 = rs 12692.30

bond = 1000( 65 - 470/13 - 165/13) = 21/13 =   rs 16153.85

Similar questions