Math, asked by aishabhata786, 7 months ago

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Answered by amitnrw
1

Given : O is the centre of the circle  of diameter d

To Find : which is bigger, 3d or  the perimeter of ΔABC

Solution:

Sum of two sides of triangle is greater than third side

in ΔAOB

OA + OB > AB

in Δ BOC

OB + OC > BC

in Δ AOC

OA + OC > AC

Adding all three

OA + OB + OB + OC + OC + OA  > AB + BC + AC

OA = OB = OC = Radius = diameter/2 = d/2

=> d/2 + d/2 +d/2 +d/2 +d/2 +d/2 > AB + BC + AC  

=> 3d > AB + BC + AC  

AB + BC + AC   = perimeter of  ΔABC

=> 3d >  perimeter of  ΔABC

3d is bigger than perimeter of ΔABC

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Answered by Anonymous
0

Answer:

Step-by-step explanation: bhen ab bhi to tamij se baat ki phale hi kar leti

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