Question

aarghhh ¡¡ Is there any real math aryabhatt? i am so angry nobody answers the question here¡ everybody here is Just to chat..



the cutie is jiminie¡ google him if u wanna know!! But answer me plz​

Answer 1

Answer:

$let \: \: {2}^{1\over3} = y \: \: also \: \: y {}^{3} = 2 \\ x = 2+ {y}^{2} + y \\ (x - 2) {}^{3} = ({y}^{2} + y) {}^{3} \\ \\ use \: \: (a + b) {}^{3} = a {}^{3} + b {}^{3} + 3ab(a + b) \\ \\ {x}^{3} - 8 - 6x(x - 2) = {y}^{6} + {y}^{3} + 3 {y}^{3} ( {y}^{2} + y) \\ {x}^{3} - 6 {x}^{2} + 12x - 8 = {y}^{6} + 3 {y}^{5} + 3 {y}^{4} + {y}^{3} \\ \\ since \: \: {y}^{3} = 2 \\ \\ {x}^{3} - 6 {x}^{2} + 12x - 8 = 4 + 6 {y}^{2} + 6y + 2 \\ {x}^{3} - 6 {x}^{2} + 12x - 8 = 6 + 6( {y}^{2} + y ) = 6 + 6(x - 2) \\ {x}^{3} - 6 {x}^{2} + 12x - 6x = 6 - 12 + 8 \\ {x}^{3} - 6 {x}^{2} + 6x = 2$

Answer 2

hope it helps you

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