Math, asked by shrikantguptajhansi, 10 months ago

-) Aarif bought a car for 12,00,000. Next year its
price decreased by 12% and further next year it
decreased by 15%. After two years the price of the
car will be
(1) 3761600
121 897600
(3) 928600
(4) 31142400
of a
naratolharam
are​

Answers

Answered by Sikshabrati
2

Answer:897600

Step-by-step explanation:

Attachments:
Answered by Soumok
23

\bf{\underline{\underline{\bigstar{Answer}}}}

\boxed{Rs 8,97,600}

Explanation :-

Original price of the car = Rs 12,00,000

Percentage decrease in the price next year = 12%

Decreased price=  \frac{12}{100}  \times 1200000

 = Rs \: 144000

Now, the price becomes = Rs (1200000 - 144000)

= Rs 10,56,000

Percentage decrease in price the next year = 15%

Decreased price = \frac{15}{100}  \times 1056000

 = Rs \: 158400

Now, the price is = Rs (1056000 - 158400)

= Rs 8,97,600

So the price after two years is Rs 8,97,600

\bf{\underline{\underline{\bigstar{Note}}}}

Decreased price = Decreased % × The amount of the previous year.

Price after deduction = Price of the previous year - Decreased price.

\bf{\underline{\underline{2nd Process}}}

In this process you can directly find out the price of the car after two years.

The formula is

CP =(1-d1/100)(1-d2/100)×Original amount

= (1-12/100)(1-15/100)×1200000

=88/100 ×85/100 ×1200000

= Rs 8,97,600

\bf{\underline{\underline{\bigstar{Note}}}}

  • CP=Car price.
  • d1= Decreased % for the 1st year.
  • d2=Decreased % for the 2nd year.

Hence, both the process are valid !

So, as per your question option 2 is correct.

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