Question

Aarohi is 5 years younger than her brother

Aditya. Four years later , Aditya will be twice as

old as Aarohi. Find their present ages.​

Answer 1

$\huge\red\star{\green{\boxed{\boxed{\mathfrak{Answer:}}}}}\red\star$

Let the present age of Aarohi be x. Then, present age of Aditya will be (x+5).

$\underline {After\; four \;years:}\\Aarohi's\; age = \bold{x+4}$

$Aditya's\; age = \bold{(x+5+4)}=\bold{x+9}$

$\large{A/q},$

$After\; four\; years,\; Aditya\; will\; be\; twice\;as\; old\; as\; Arohi.$

$\large{Then,}$

$\rm{\implies x+9=2(x+4)}$

$\rm{\implies x+9=2x+8}$

$\rm{\implies x-2x=8-9}$

$\rm{\implies -\!\!\!\!/\;x=-\!\!\!\!/\;1}$

$\rm{\implies x=1}$

$\text{Hence, Aarohi's age = x =\;1}$

$\text{and Aditya's age= x+5\;=\;1+5\;=\;6}$