Aaron has an American coin collection. He has three times as many 10 cent coins as 25 cent coins and he has some 5 cent coins as well. If he has 88 coins with a total value of $11:40, how many of each type does he have?
Answers
Answer:
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let 'x' represent the number of 25-cent coins, then '3x' represents the number of 10-cent coins and '88-x-3x' represents the number of 5-cent coins
11.40 = 0.05(88-x-3x) + 0.10(3x) + 0.25(x)
solving for 'x' we have x=20
3*20 = 60
88 - x- 3*20 = 8
Aaron has 8 n
Step-by-step explanation:
Let,
- 25 cent coins = x
- 10 cent coins = 3x
- 5 cent coins = 88 - 4x
Aaron has 88 coins
Total amount = $ 11.40
★ According to the Question :
⇒ 0.25 (x) + 0.1 (3x) + 0.05 (88 - 4x) = 11.40
⇒ 0.25x + 0.3x + 4.4 - 0.2x = 11.40
⇒ 0.25x + 0.3x - 0.2x + 4.4 = 11.40
⇒ 0.55x - 0.2x + 4.4 = 11.40
⇒ 0.35x + 4.4 = 11.40
⇒ 0.35x = 11.40 - 4.4
⇒ 0.35x = 7
⇒ x = 7 / 0.35
⇒ x = 20
25 cent coins = 20
• 10 cent coins = 3x
⇒ 3 × 20
⇒ 60
10 cent coins = 60
• 5 cent coins = 88 - 4x
⇒ 88 - (4 × 20)
⇒ 88 - 80
⇒ 8
5 cent coins = 8
Total coins = 88 (20 + 60 + 8)
Therefore, Aaron has :
- 25 cent coins = 20
- 10 cent coins = 60
- 5 cent coins = 8