Question

Aaron is 5 years younger than Ron. Four years later, Ron will be twice as old as Aaron. Find their present ages.

Answer 1

Answer:

Ron's age=x

Aaron's age=x-5

4 years later.,

Ron's age=x+4

Aaron's age=x-5+4

A/Q,

x x+4

=>--- = -----

x-5 x-5+4

x x+4

=> ---- = -------

x-5 x-1

=>2x-1 = (x-5)(x+4)

=>2x-1 =x(x+4) - 5(x+4)

2

=> 2x-1 = x+4x-5x+20

2

=>2x-1 = x - 1+20

2

=>2x-1 = x +19

2

=>2x. x =19+1

3

=>2x = 20

3 20

=>x= ----

2

3

=>x= 2

Answer 2

Given:-

• Aaron is 5 years younger than Ron.
• 4 years later, Aaron will be twice as old as Ron.

To find:-

• Find their present ages ?

Solutions:-

• Let the present age of Aaron be 'x' years.
• Let the present age of Ron be 'y' years

According to question:-

Aaron is 5 years younger than Ron

=> x = y + 5 .......(i).

4 years later Aaron will be twice as old as Ron

• Aaron's age = (x+ 4) years
• Ron's age = (y+4) years

=> (x + 4) = 2(y + 4)

=> x + 4 = 2y + 8

=> x - 2y = 8 - 4

=> x - 2y = 4

Putting the value of 'x' from equation (i)

=> x - 2y = 4

=> y + 5 - 2y = 4

=> -y = 4 - 5

=> -y = -1

=> y = 1

Putting the value of 'y' in equation (i)

=> x = y + 5

=> x = 1 + 5

=> x = 6

Hence, the age of Aaron is 6 years and the age of Ron is 1 year.