Math, asked by Anonymous, 4 months ago

Aaron is 5 years younger than Ron. Four years later, Ron will be twice as old as Aaron. Find their present ages.

Answers

Answered by Anonymous
0

Answer:

Let the present age of Aaron be 'x' years.

Let the present age of Ron be 'y' years

Aaron is 5 years younger than Ron

=> x = y + 5 .......(i).

4 years later Aaron will be twice as old as Ron

Aaron's age = (x+ 4) years

Ron's age = (y+4) years

=> (x + 4) = 2(y + 4

Step-by-step explanation:

Answered by ri4
0

Given:

Aaron is 5 years younger than Ron.

4 years later, Aaron will be twice as old as Ron.

Find:

Their present ages

Solution:

Let the present age of Aaron be 'x' years.

Let the present age of Ron be 'y' years

Aaron is 5 years younger than Ron

=> x = y + 5 .......(i).

4 years later Aaron will be twice as old as Ron

Aaron's age = (x+ 4) years

Ron's age = (y+4) years

=> (x + 4) = 2(y + 4)

=> x + 4 = 2y + 8

=> x - 2y = 8 - 4

=> x - 2y = 4

Putting the value of 'x' from equation (i)

=> x - 2y = 4

=> y + 5 - 2y = 4

=> -y = 4 - 5

=> -y = -1

=> y = 1

Putting the value of 'y' in equation (i)

=> x = y + 5

=> x = 1 + 5

=> x = 6

Hence, the age of Aaron is 6 years and the age of Ron is 1 year.

I hope it will help you.

Regards.

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