Question

aata hai toh hi solve karna ​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

Here x2 = a2 sec2 θ + 2ab sec θ tan θ + b2 tan2 θ

y2 = a2 tan2 θ + 2 ab sec θ tan θ + b2 sec2 θ

⇒ x2 – y2 = a2(sec2 θ – tan2 θ) – b2 (sec2 θ – tan2 θ)

= a2 – b2 (∵ sec2 θ – tan2 θ = 1)