Aayush course three times around the rectangular field who length and breadth are 25 and 19 rectangular how much distance does he cover
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Answered by
6
Given :
- Aayush course three times around the rectangular field who length and breadth are 25 and 19 rectangular
To find :
- how much distance does he cover
Solution :
Perimeter of the field
=2(l + b)
= 2(25 m + 19 m)
=2 x 44 m
= 88 m
Total Distance covered by Akshay
= 3 x 88 m
= 264 m
Hence the required distance = 264 m.
Extra information :
- Volume of cylinder = πr²h
- T.S.A of cylinder = 2πrh + 2πr²
- Volume of cone = ⅓ πr²h
- C.S.A of cone = πrl
- T.S.A of cone = πrl + πr²
- Volume of cuboid = l × b × h
- C.S.A of cuboid = 2(l + b)h
- T.S.A of cuboid = 2(lb + bh + lh)
Answered by
41
Answer:
⭐ Given ⭐
Aayush course three times around the rectangular field whose length and breadth are 25cm and 19cm.
⭐ To Find ⭐
How much distance does he cover.
⭐ Solution ⭐
➕ Length of the rectangular field (l) = 25cm
➕ Breadth of the rectangular field (b) = 19 cm
✳️ Perimeter of the rectangular field (P)
2(l + b) m
2(25 + 19) m
2 × 44 m
88 m
Distance cover :-
3P
3 × 88
264 m
✴️ The required distance will be 264 m.
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