Math, asked by PrerakPatel3794, 7 months ago

Aayush course three times around the rectangular field who length and breadth are 25 and 19 rectangular how much distance does he cover

Answers

Answered by Anonymous
6

Given :

  • Aayush course three times around the rectangular field who length and breadth are 25 and 19 rectangular

To find :

  • how much distance does he cover

Solution :

Perimeter of the field

=2(l + b)

= 2(25 m + 19 m)

=2 x 44 m

= 88 m

Total Distance covered by Akshay

= 3 x 88 m

= 264 m

Hence the required distance = 264 m.

Extra information :

  • Volume of cylinder = πr²h
  • T.S.A of cylinder = 2πrh + 2πr²
  • Volume of cone = ⅓ πr²h
  • C.S.A of cone = πrl
  • T.S.A of cone = πrl + πr²
  • Volume of cuboid = l × b × h
  • C.S.A of cuboid = 2(l + b)h
  • T.S.A of cuboid = 2(lb + bh + lh)

Answered by misscutie94
41

Answer:

⭐ Given ⭐

\mapsto Aayush course three times around the rectangular field whose length and breadth are 25cm and 19cm.

To Find

\mapsto How much distance does he cover.

Solution

Length of the rectangular field (l) = 25cm

Breadth of the rectangular field (b) = 19 cm

✳️ Perimeter of the rectangular field (P)

\implies 2(l + b) m

\implies 2(25 + 19) m

\implies 2 × 44 m

\dashrightarrow 88 m

\therefore Distance cover :-

\implies 3P

\implies 3 × 88

\dashrightarrow 264 m

✴️ The required distance will be 264 m.

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