Question

Aayush Shri sat for 6th and Ananya 847 test their percentage scores were:ayushree 68,75,70,45,57,77
ANANYA
52,87,64,53,74,81,86
who has the higher means score ?​

Answer 1

Question:-

Aayush Shri sat for 6th and Ananya 7th test their percentage scores were..

$\begin{array}{|c|c|c|c|c|c|c|c|}\cline{1-8}Aayush\: Shri & 68 & 75 & 70 & 45 & 57 & 77 & \\ \cline{1-8} Ananya & 52 & 87 & 64 & 53 & 74 & 81 & 86 \\ \cline{1-8}\end{array}$

Who has the higher mean score?

Solution:-

Mean is defined as the sum of all observations divide by total number of observations.

Here,

Sum of observations = Sum of Aaayush Shri's number

And total number of observations = 6

Let's denote the Aaysh Shri's number by x.

$\implies\:\sf{x\:=\:\dfrac{\Sigma f_i x_i}{\Sigma f_i}}$

$\Rightarrow\:\sf{x\:=\:\frac{68+75+70+45+57+77}{6}}$

$\Rightarrow\:\sf{x\:=\:\frac{392}{6}}$

$\Rightarrow\:\sf{x\:=\:65.33}$

Similarly,

Let's denote the Ananya's number by y.

Now,

Sum of observations = Sum of Ananya's number

And total number of observations = 7

$\implies\:\sf{y\:=\:\dfrac{\Sigma f_i y_i}{\Sigma f_i}}$

$\Rightarrow\:\sf{y\:=\:\frac{52+87+64+53+74+81+86}{7}}$

$\Rightarrow\:\sf{y\:=\:\frac{497}{7}}$

$\Rightarrow\:\sf{y\:=\:71}$

Now compare the percentage score of of Aayush Shri and Ananya.

On comparing, we found that;

Ananya score's 5.67 more than Aayash Shri.

Therefore,

Ananya has the higher mean score.

Answer 2

$\Large\underline{\underline{\sf{Given}:}}$

Ayushree marks = 68,75,70,45,57 and 77.

Ananya marks = 52,87,64,53,74,81 and 86.

$\Large\underline\mathfrak{Question}$

$\textbf{who has the higher means score ?}$

_______________________________

$\green{\textsf{Mean. The mean (or average) of a }} \\ \green{\textsf{set of data values is the sum of all of }} \\ \green{\textsf{the data values divided by the}} \\ \green{\textsf{number of data values.}} \\ \\ \boxed{ \sf \: mean = \dfrac{sum \: of \: observation}{number \: of \: observation}}$

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$\sf \: mean \: marks \: for \: ayshuree = \\ \\ = \pink{\dfrac{68 + 75 + 70+45 + 57 + 77}{6}} \\ \\ = \dfrac{392}{6} \\ \\ = \red{65.33}$

______________________________________

$\sf \: mean \: marks \: for \: ananya = \\ \\ = \pink{\dfrac{52 + 87 + 64+53 + 74 +81 + 86}{7}} \\ \\ = \dfrac{497}{7} \\ \\ = \red{71}$

____________________________________

$\large\textbf{ \red{Ananya} has higher mean score.}$

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$\large\underline\textbf{Hope it Helps You.}$

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