ab=10a+b
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Let the two digit number be 10a+b
N = 10a+b
N' = reversed number = 10b+a
N-N' = 9(a-b)
N-N' is positive perfect cube.
∴ a>b
For 9(a-b) be perfect cube, a-b = 3
∴ b ϵ [0, 6] ⟶ 7 values
∴ a ϵ [3, 9] ⟶ 7 values
∴ Total 7 values are possible for N.
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