AB=12 AD:DB=5:7 точка D принадлежит отрезку AB
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В треугольнике ABC, AB = 15, BC = 7, CA = 9. Точка D лежит на прямой BC причем BD : DC = 5 : 7. ... ADC и ADB касаются стороны AD в точках E и F. Найдите длину отрезка EF.
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Let AD and DB be 5x and 7x
As D lies on AB
AD + DB = AB
5x + 7x = 12
12x = 12
x = 1
therefore, AD = 5 and DB = 7
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