AB = 17 CD = 16 find OM AMD ON
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AO^2 = AM^2+ OM^2
5^2 = 8.5 ^ 2 + OM^2
OM^2 = 47.25
OM = 6.8
5^2 = 8.5 ^ 2 + OM^2
OM^2 = 47.25
OM = 6.8
pranjal3828:
6.8 × 2 = ON = 13.6
What is this i didnt understand
I didnt understood
the line which passes through the centre of the circle cut the cord into two equal sizes show half of 17 is 8.5 and half of 16 is 8
who is the radius of the circle that means 5 cm . AO MO AND AM makesPythagoras Theorem that means AO^2 = AM^2 + OM^2
6.8×2 means the line which cut the cord is divided into equal party OM equals to 6.8 THEN NO = 2 OM
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