Math, asked by shivajicy, 11 months ago

(ab^2)^3×(-a)^-2×1/(b^-2)^5​

Answers

Answered by Aditi2775
3

Answer:

ab^16

Step-by-step explanation:

(ab^2)^3 * 1/(-a)^2 * b^10

a^3 b^6 * 1/a^2 * b^10

after cancelling 'a'

=ab^16

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