Math, asked by SiddhantMohile, 1 year ago

ab^2-(a-c)b-c factorise

Answers

Answered by Anonymous
4

Solution

ab²-(a-c)b-c

=ab²-ab+bc-c

=ab(b-1)+c(b-1)

=(b-1)(ab+c)

Answered by Anonymous
17

Step-by-step explanation:

ab²-(a-c)b-c

=ab²-ab+bc-c

=ab(b-1)+c(b-1)

=(b-1)(ab+c)

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