ab^2-(a-c)b-c factorise
Answers
Answered by
4
Solution
ab²-(a-c)b-c
=ab²-ab+bc-c
=ab(b-1)+c(b-1)
=(b-1)(ab+c)
Answered by
17
Step-by-step explanation:
ab²-(a-c)b-c
=ab²-ab+bc-c
=ab(b-1)+c(b-1)
=(b-1)(ab+c)
Similar questions