Question

(ab-2) (ab+4) find the product​

Answer 1

Answer:

Using the formula (x + a)(x + b)= x^2 + (a+b)x + ab,

ab^2 + (4-2)ab + (-8)

(ab)^2 + 2ab - 8____Ans.

Answer 2

Answer:

Required product is ${a}^{2} {b}^{2} + 2ab - 8$

Step-by-step explanation:

Given two terms are $(ab - 2)$ and (ab+4)

We want to find product of these two terms.

We know,

$(x + p)(x + q) \\ = x \times x + p \times x + q \times x + p \times q \\ = {x}^{2} + px + qx + pq$

Now,

$(ab - 2)(ab + 4) \\ = ab \times ab + 4 \times ab - 2 \times ab - 2 \times 4 \\ = {(ab)}^{2} + 4ab - 2ab - 8 \\ = {a}^{2} {b}^{2} + 2ab - 8$

This is a problem of product of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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