Question

Ab - 2a2 + ac factorization

Answer 1

Given : 2a

2

+bc−2ab−ac

We can further write it as

2a

2

+bc−2ab−ac =2a

2

−2ab−ac+bc

By taking the common terms out

2a

2

+bc−2ab−ac =2a(a−b)−c(a−b)

So we get,

2a

2

+bc−2ab−ac =(a−b)(2a−c)