ab =3:5 and cb= 2:1 find largest angle option
A 130
B 100
C 80
D 110
E 136
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a:b:c = 3: 5: 10
now let the common ratio = x
a= 3x , b= 5x , c= 10x
a° + b° + c° = 180° ( supplementary angles)
3x + 5x + 10x = 180°
18x = 180°
x = 10°
so the largest angle is c = 10 × 10
100°( B)
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