Question

AB= 3x, BC= 3x/2. Find AC by pythagoras theorem.
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Answer 1

Answer:

AC=3root5/2

Step-by-step explanation:

AC^2=AB^2 +BC^2

》AC^2=(3x)^2+(3x/2)^2

》AC^2 =9X^2 + 9X^2/4

》AC^2=45x^2/4

》AC=3root 5/2 (by removing square root)

Answer 2

Answer:

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Step-by-step explanation:

$Given \: , AB = 3x$

$and, \: BC = \frac{3x}{2}$

$Pythagoras \: theorem \: states \: that :$

$AC² =AB²+ BC²$

$=> AC² = (3x)² + (\frac{3x}{2} )²$

$AC² = 9x²+\frac{9x²}{4}$

$=> \frac{36x²+9x²}{4}$

$= \frac{45x²}{4}$

$= √ \frac{45x²}{4}$

$= \frac{3x \sqrt{5} }{2}$

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