AB = 4.5 cm, angle B = 120° and the distance between AB and DC = 3.0 cm.
Construct a parallelogram ABCD
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Draw a line segment AB=4.5cm.
⇒ Construct an angle of 120∘ at B.
⇒ We have given that distance between AB and DC is 3cm, then AD=BC=3 cm.
⇒ Since it's parallelogram and AD = BC then, AB = CD.
⇒ With B as a center and radius 3 cm then cut off at point C.
⇒ With C as center and radius CD =4.5 cm draw an arc.
⇒ Then with A as center and radius AD =3 cm draw an arc intersecting at point D.
⇒ Join AD and CD.
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