Math, asked by chinnidharani1234, 3 months ago

ab=4cm,∆B=70°,∆C=30°,scale factor 7/5​

Answers

Answered by branilyqueen10
4

Maths

Construct a △ABC in which AB=4 cm, BC=5 cm and AC=6 cm. Now, construct a triangle similar to △ABC such that each of its sides is two-third of the corresponding sides of △ABC. Also, prove your assertion. 

Answer

Steps:

1. draw base AB=4cm

2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc.

3. let C be the point of intersection of the above 2 lines.

4. draw a ray AX making an acute angle with line AB on the opposite side if the vertex C. 

5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1

6. join A3B and draw a parallel line B′A2

7. draw a line parallel to BC  to intersect AC at C′

Thus AB′C′ is a required triangle.

Justification;

By construction,

ABAB′=AA3AA2=32

also B′C′∥BC

∴∠AB′C′=∠ABC

In △AB′C′,△ABC

∠A=∠A

∠AB′C′=∠ABC

△AB′C′∼△ABC

⇒ABAB

Attachments:

chinnidharani1234: diagram plz
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