ab= 5, a-b=4, . find (A3+b3)
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Given: ab=5
a-b=4....(A)
Solution: We have a-b=4
Squaring, we get
a²+b²-2ab=16
a²+b²-10=16 (since ab=5)
a²+b²=26...(1)
But we know that
(a+b)²=a²+b²+2ab
OR
a²+b²= (a+b)²-2ab
Using this, we can modify (1) as
(a+b)²-2ab=26
(a+b)²-10=26
(a+b)²=36
a+b = ±6...(B)
Solving (A) and (B), we get
a=5, b=1
OR
a= -1, b= -5
Hence a³+b³=126. OR. a³+b³= -126
Hope it helps
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