Question

ab=5 , a-b = 4, then value of a^3+b^3​

Answer 1

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Step-by-step explanation:

Text solution

a^3 −b^3 =(a−b)(a^2 +ab+b^2 )

a^3 −b^3 =(a−b)(a^2 +ab+b^2 )ab = 5

a^3 −b^3 =(a−b)(a^2 +ab+b^2 )ab = 5 a - b = 4

a^3 −b^3 =(a−b)(a^2 +ab+b^2 )ab = 5 a - b = 4 a^3 - b^3 = (a-b)(a^2-2ab+b^2+2ab+ab)

a^3 −b^3 =(a−b)(a^2 +ab+b^2 )ab = 5 a - b = 4 a^3 - b^3 = (a-b)(a^2-2ab+b^2+2ab+ab)a^3 - b^3 = (a-b)(a-b)^2 + 3ab)

a^3 −b^3 =(a−b)(a^2 +ab+b^2 )ab = 5 a - b = 4 a^3 - b^3 = (a-b)(a^2-2ab+b^2+2ab+ab)a^3 - b^3 = (a-b)(a-b)^2 + 3ab) a^3 - b^3 = 4(4^2+3×5)

a^3 - b^3 = 4×(16+15)

a^3 - b^3 = 4×31

a^3 - b^3 = 124

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